Calculus II
Contents
Series
Integrals
Definite integrals
Some primitives
Numerical methods
Exercices
© The scientific sentence. 2010
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Calculus II:
Definite integral
numerical approaches
Rectangles method
Before integration was developed by Newton and Leibniz,
, mainly the Fundamental Theorem of Calculus,
the way to find the area under curves ( for example under
an arch) is to add areas of rectangles.
Adding rectangles
We divide the space under the curve into rectangles and add the areas of those rectangles.
The height of each rectangle is the function value of each corresponding
width (Δx).
We get a better result if we take more and more rectangles.
In the Rectangles method, we approximate the area
using rectangles .
Using rectangles, to calculate the area under the curve, we will consider
three cases :
1. Outer rectangles:
We add the areas of the "outer" rectangles:
A = Δx f(Δx) + Δx f(2Δx) + ... +
Δx f(3Δx) + Δx f(4Δx).
Generally,
A = Δx f(Δx) + Δx f(2Δx) + ... +
Δx f(nΔx)
Δx [f(Δx) + f(2Δx) + ... + f(nΔx) ]
2. Inner rectangles:
We add the areas of the "inner" rectangles.:
A = Δx f(0) + Δx f(Δx) +
Δx f(2Δx) ) + Δx f(3Δx) +
Δx f(4Δx)]
Generally,
A = Δx f(0) + Δx f(Δx) + ... + Δx f((n - 1)Δx)
A =
Δx [f(0) + f(Δx) + ... + f((n - 1)Δx) ]
3. mid-point rectangles.
A third way of doing this problem would be to find the mid-point
rectangles.
A = (Δx/2) f(Δx ) + (3/2)Δx f(2Δx) +
(5/2)Δx f(3Δx) + (7/2)Δx f(4Δx)
Generally,
A = (Δx/2) f(Δx ) + (3/2)Δx f(2Δx) +
(5/2)Δx f(3Δx) +
... + (n - 1/2)Δx f(nΔx)
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