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Functionals:
Variational Methods
Euler-Lagrange equation simplified
Beltrami formula





1. The other form of Euler-Lagrange equation


Here is the Euler-Lagrange equation:

∂f/∂y - d[∂f/∂y']/dx = 0 .

For the second term, the total differential is:

d[∂f/∂y'] = ∂[∂f/∂y']/∂y dy + ∂[∂f/∂y']/∂y' dy' + ∂[&partf/∂y']/∂x dx = (∂2f/∂y'∂y)dy + (∂2f/∂y'2)dy' + (∂2f/∂y'∂x)dx.

Threfore:

d[∂f/∂y']/dx = (∂2f/∂y'∂y)y' + (∂2f/∂y'2)y" + ∂2f/∂y'∂x .

If the functional f does not depend explicitly on x, that is ∂f/∂x = 0 ; the last term in the latter equation vanishes, and the differential becomes:

d[∂f/∂y']/dx = (∂2f/∂y'∂y)y' + (∂2f/∂y'2)y" .

Therefore, the Euler-Lagrange equation becomes.

∂f/∂y - (∂2f/∂y'∂y)y' - (∂2f/(∂y')2)y" = 0

∂f/∂y - (∂2f/∂y'∂y)y' - (∂2f/∂y'2)y" = 0



2. Euler-Lagrange equation simplified


On the other hand, we have :

d[f - y'(∂f/∂y')]/dx =

(∂f/∂y) y' + (∂f/∂ y')y" + ∂f/∂x - y"(∂f/∂y') - y'[(∂2f/∂y'∂y)y' + (∂2f/∂y'2)y" + (∂2f/∂y'∂x) ] =
(∂f/∂y) y'+ (∂f/∂y')y" - y"(∂f/∂y') - (∂2f/∂y'∂y)y'2 - (∂2f/∂y'2)y"y' ] =
y' [(∂f/∂y) - (∂2f/∂y'∂y)y' - (∂2f/∂y'2)y"]

According to the above second form of Euler-Lagrange equation, the sum of the terms between the brackets is equal to zero, therefore:

d[f - y'(∂f/∂y')]/dx = 0 . So

If the functional f does not depend on x, that is
∂f/∂x = 0 , then:

d[f - y'(∂f/∂y')]/dx = 0

This is the simplified Euler-Lagrange equation. We can express it as

f - y'(∂f/∂y') = constant.

called Beltrami formula.




  


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