Class B Network |
Class B: 255.255.xxx.yyy xxx : from 0 to 255 yyy : from 0 to 255 We mask as follows: -- As in class C.0,, that is we vary xxx and we fix yyy 255.255.0.0 255.255.128.0 255.255.192.0 255.255.224.0 255.255.240.0 255.255.248.0 255.255.252.0 255.255.254.0 And As the class C, that is we fix xxx = 255 and we vary yyy 255.255.255.0 255.255.255.128 255.255.255.192 255.255.255.224 255.255.255.240 255.255.255.248 255.255.255.252 We do not vary xxx and yyy at the same time. But Subnet Bits: Number of bits masked (equal to 1) ------------------ Class B Formulas: ------------------ IP Address:xxx.yyy.zzz.vvv where the First Octet Range xxx's is: 128 - 191. and the Second, third and fourth Octet Range is: 0 - 255 Mask : One of the elemnts of the following array: In decimal: [M] = {128, 192, 224, 240, 248, 252, 254, 255} In binary: [M] = {10000000, 11000000, 11100000, 11110000, 11111000, 11111100, 11111110, 1111111} Subnet Bits = the number of 1 in binary's representation of the Mask Subnet Mask: 255.255.m.0 and 255.255.255.m (m belongs to [M]) Max Subnet = 2Subnet Bits Number of Hosts = (256 - Mask) x 256 - 2 - 2 stands for that we reseve the first and the last host addresses: The first is called Subnet ID, the second Broadcast Address Subnet ID = xxx.yyy.0.0 Broadcast Address: xxx.yyy.(255 - Mask). (255 -Mask) Wildcard Mask: 0.0.(255 - Mask).255 Host Address Range: xxx.yyy.0.1 - xxx.yyy.(255 - Mask).254 -------------- Subnet Mask Subnet Max Bits Subnet Hosts 0 255.255.0.0 Subnet Bits = 0 Max Subnet = 1 Hosts = 256 x 256 - 2 = 65534 1 255.255.128.0 Subnet Bits = 1 Max Subnet = 2 Hosts = 128 x 256 - 2 = 32766 2 255.255.192.0 Subnet Bits = 2 Max Subnet = 4 Hosts = 64 x 256 - 2 = 16382 3 255.255.224.0 Subnet Bits = 3 Max Subnet = 8 Hosts = 32 x 256 - 2 = 8190 4 255.255.240.0 Subnet Bits = 4 Max Subnet = 16 Hosts = 16 x 256 - 2 = 4094 5 255.255.248.0 Subnet Bits = 5 Max Subnet = 32 Hosts = 8 x 256 - 2 = 2046 6 255.255.252.0 Subnet Bits = 6 Max Subnet = 64 Hosts = 4 x 256 - 2 = 1022 7 255.255.254.0 Subnet Bits = 7 Max Subnet = 128 Hosts = 2 x 256 - 2 = 510 And As the class C 8 255.255.255.0 Subnet Bits = 8 Max Subnet = 256 256 - 2 = 254 9 255.255.255.128 Subnet Bits = 9 Max Subnet = 512 128 - 2 = 126 10 255.255.255.192 Subnet Bits = 10 Max Subnet = 1024 64 - 2 = 62 11 255.255.255.224 Subnet Bits = 11 Max Subnet = 2048 32 - 2 = 30 12 255.255.255.240 Subnet Bits = 12 Max Subnet = 4096 16 - 2 = 14 13 255.255.255.248 Subnet Bits = 13 Max Subnet = 8192 8 - 2 = 6 14 255.255.255.252 Subnet Bits = 14 Max Subnet = 16384 4 - 2 = 2 Subnet ID Example: 172.32.0.0 ----------- From 0 - 7: ----------- Hosts = (256 - Mask) x 256 - 2 Mask: 0 Broadcast Address: 172.32.255.255 0 + 255 = 255 Host Address Range: 172.32.0.1 - 172.32.255.254 Mask: 128 Broadcast Address: 172.32.127.255 128 + 127 = 255 Host Address Range: 172.32.0.1 - 172.32.127.254 Mask: 192 Broadcast Address: 172.32.63.255 192 + 63 = 255 Host Address Range: 172.32.0.1 - 172.32.63.254 Mask: 224 Broadcast Address: 172.32.31.255 Wildcard Mask: 0.0.31.255 224 + 31 = 255 Host Address Range: 172.32.0.1 - 172.32.31.254 Mask: 240 Broadcast Address: 172.32.15.255 Wildcard Mask: 0.0.15.255 240 + 15 = 255 Host Address Range: 172.32.0.1 - 172.32.15.254 Mask: 248 Broadcast Address: 172.32.7.255 Wildcard Mask: 0.0.7.255 248 + 7 = 255 Host Address Range: 172.32.0.1 - 172.32.7.254 Mask: 252 Broadcast Address: 172.32.3.255 Wildcard Mask: 0.0.3.255 252 + 3 = 255 Host Address Range: 172.32.0.1 - 172.32.3.254 Mask: 254 Broadcast Address: 172.32.1.255 Wildcard Mask: 0.0.1.255 254 + 1 = 255 Host Address Range: 172.32.0.1 - 172.32.1.254 ------------- From 8 - 15 : ------------ Hosts = (256 - Mask) - 2 Mask: 0 Broadcast Address: 172.32.0.255 0 + 255 = 255 Host Address Range: 172.32.0.1 - 172.32.0.254 Mask: 128 Broadcast Address: 172.32.0.127 128 + 127 = 255 Host Address Range: 172.32.0.1 - 172.32.0.126 Mask: 192 Broadcast Address: 172.32.0.63 192 + 63 = 255 Host Address Range: 172.32.0.1 - 172.32.0.62 Mask: 224 Broadcast Address: 172.32.0.31 224 + 31 = 255 Host Address Range: 172.32.0.1 - 172.32.0.30 Mask: 240 Broadcast Address: 172.32.0.15 240 + 15= 255 Host Address Range: 172.32.0.1 - 172.32.0.14 Mask: 248 Broadcast Address: 172.32.0.7 248 + 7 = 255 Host Address Range: 172.32.0.1 - 172.32.0.6 Mask: 252 Broadcast Address: 172.32.0.3 252 + 3 = 255 Host Address Range: 172.32.0.1 - 172.32.0.2 |